The number of meso forms of the given compoun | vedclass

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(A) The compound $CH_3-CH(OH)-CH(OH)-CH(OH)-CH_3$ is a symmetric molecule with $n=3$ chiral centers (where the middle carbon is a pseudo-asymmetric ce

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(A) The compound $CH_3-CH(OH)-CH(OH)-CH(OH)-CH_3$ is a symmetric molecule with $n=3$ chiral centers (where the middle carbon is a pseudo-asymmetric center). For a symmetric molecule with an odd number of chiral centers $(n)$,the number of meso forms is given by the formula: $2^{(n-1)/2}$. Here,$n = 3$. Number of meso forms = $2^{(3-1)/2} = 2^1 = 2$. The two meso forms are $(2R, 3r, 4S)$ and $(2R, 3s, 4S)$.

The number of meso forms of the given compound $CH_3-CH(OH)-CH(OH)-CH(OH)-CH_3$ is

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