The number of molecules in 4.25 , g of ammoni | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The molecular weight of $NH_3$ is $17 \, g/mol$.According to the mole concept,$17 \, g$ of $NH_3$ contains $6.022 	imes 10^{23}$ molecules.Theref

Vedclass · Accepted Answer

$1.5 	imes 10^{23}$

Vedclass · Answer

(B) The molecular weight of $NH_3$ is $17 \, g/mol$.According to the mole concept,$17 \, g$ of $NH_3$ contains $6.022 	imes 10^{23}$ molecules.Therefore,the number of moles in $4.25 \, g$ of $NH_3$ is $\frac{4.25 \, g}{17 \, g/mol} = 0.25 \, mol$.The number of molecules $= 	ext{moles} 	imes N_A = 0.25 	imes 6.022 	imes 10^{23} \approx 1.505 	imes 10^{23}$ molecules.Thus,the correct option is $(B)$.

The number of molecules in $4.25 \, g$ of ammonia is:

Similar Questions

Which of the following contains the maximum number of atoms?

$A$ gas mixture contains $50\%$ helium and $50\%$ methane by volume. What is the percent by weight of methane in the mixture?

The number of oxygen atoms in $4.4 \ g$ of $CO_2$ is approximately ........ $\times 10^{23}$.

One mole of a gas represents......

Two vessels $A$ and $B$ of $1 \, L$ each contain $0.11 \, g$ $CO_2$ gas and $0.07 \, g$ of unknown gas respectively under the same conditions of pressure and temperature. The unknown gas is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module