The number of molecules in 4.25 g of ammonia | vedclass

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Question

(B) The molar mass of ammonia $(NH_3)$ is $14 + (3 	imes 1) = 17 \ g/mol$.Number of moles of $NH_3 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \f

Vedclass · Accepted Answer

$1.5 	imes 10^{23}$

Vedclass · Answer

(B) The molar mass of ammonia $(NH_3)$ is $14 + (3 	imes 1) = 17 \ g/mol$.Number of moles of $NH_3 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{4.25 \ g}{17 \ g/mol} = 0.25 \ mol$.Number of molecules = $	ext{Number of moles} 	imes N_A = 0.25 	imes 6.022 	imes 10^{23} \approx 1.505 	imes 10^{23}$.Thus,the number of molecules is approximately $1.5 	imes 10^{23}$.

The number of molecules in $4.25 \ g$ of ammonia is approximately

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