The number of molecules in 16 g of methane i | vedclass

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(B) Given mass of methane $(CH_4) = 16 \ g$.Molar mass of $CH_4 = 12 + (4 	imes 1) = 16 \ g/mol$.Moles of $CH_4 = \frac{	ext{Given mass}}{	ext{Mola

Vedclass · Accepted Answer

$6.02 	imes 10^{23}$

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(B) Given mass of methane $(CH_4) = 16 \ g$.Molar mass of $CH_4 = 12 + (4 	imes 1) = 16 \ g/mol$.Moles of $CH_4 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{16 \ g}{16 \ g/mol} = 1 \ mol$.Since $1 \ mol$ of any substance contains $6.022 	imes 10^{23}$ molecules (Avogadro's number),Therefore,$1 \ mol$ of $CH_4$ contains $6.02 	imes 10^{23}$ molecules.

The number of molecules in $16 \ g$ of methane is

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