The number of monochloro-products formed from | vedclass

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(C) The structure of $n-$butane is $CH_3-CH_2-CH_2-CH_3$.Chlorination of $n-$butane can occur at the $C-1$ position or the $C-2$ position.Substitution

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$3$

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(C) The structure of $n-$butane is $CH_3-CH_2-CH_2-CH_3$.Chlorination of $n-$butane can occur at the $C-1$ position or the $C-2$ position.Substitution at $C-1$ gives $1-$chlorobutane $(CH_3-CH_2-CH_2-CH_2Cl)$.Substitution at $C-2$ gives $2-$chlorobutane $(CH_3-CH_2-CHCl-CH_3)$.Since $2-$chlorobutane has a chiral center,it exists as a pair of enantiomers ($d$ and $l$ forms).Therefore,the total number of distinct monochloro-products (including stereoisomers) is $3$ ($1-$chlorobutane,$d-2-$chlorobutane,and $l-2-$chlorobutane).

The number of monochloro-products formed from $n-$butane is:

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