The number of no bond resonance structures po | vedclass

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Question

(C) No bond resonance (hyperconjugation) depends on the number of $\alpha-H$ atoms.For but$-1-$ene $(CH_3-CH_2-CH=CH_2)$,the $\alpha$-carbon is the $C

Vedclass · Accepted Answer

$2, 7$

Vedclass · Answer

(C) No bond resonance (hyperconjugation) depends on the number of $\alpha-H$ atoms.For but$-1-$ene $(CH_3-CH_2-CH=CH_2)$,the $\alpha$-carbon is the $CH_2$ group attached to the double bond. It has $2$ $\alpha-H$ atoms. Therefore,it gives $2$ no bond resonating structures.For a $3^{\circ}$ carbocation with methyl $(-CH_3)$,ethyl $(-CH_2CH_3)$,and isobutyl $(-CH_2CH(CH_3)_2)$ groups attached to the cationic carbon,the total number of $\alpha-H$ atoms is calculated as follows:- From methyl group: $3$ $\alpha-H$- From ethyl group: $2$ $\alpha-H$- From isobutyl group: $2$ $\alpha-H$Total $\alpha-H = 3 + 2 + 2 = 7$.Thus,it forms $7$ no bond resonating structures.Hence,option $(C)$ is correct.

The number of no bond resonance structures possible for but$-1-$ene and a $3^{\circ}$ carbocation having methyl,ethyl,and isobutyl groups on the cationic carbon,respectively,are:

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