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(C) The structure of $2-$Bromo$-3-$chlorobutane is $CH_3-CH(Br)-CH(Cl)-CH_3$.This molecule contains two chiral centers (at $C-2$ and $C-3$).Since the

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$4$

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(C) The structure of $2-$Bromo$-3-$chlorobutane is $CH_3-CH(Br)-CH(Cl)-CH_3$.This molecule contains two chiral centers (at $C-2$ and $C-3$).Since the molecule does not have a plane of symmetry (the groups attached to the chiral centers are different),the number of optical isomers is given by $2^n$,where $n$ is the number of chiral centers.Here,$n = 2$.Therefore,the number of optical isomers $= 2^2 = 4$.The four isomers are $(2R, 3R)$,$(2S, 3S)$,$(2R, 3S)$,and $(2S, 3R)$.

The number of optical isomers possible for $2-$Bromo$-3-$chlorobutane are

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