The number of oxygen atoms in 4.4 g of CO_2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The molar mass of $CO_2$ is $12 + (2 	imes 16) = 44 \ g/mol$. Moles of $CO_2 = \frac{	ext{given mass}}{	ext{molar mass}} = \frac{4.4 \ g}{44 \

Vedclass · Accepted Answer

$1.2 	imes 10^{23}$

Vedclass · Answer

(A) The molar mass of $CO_2$ is $12 + (2 	imes 16) = 44 \ g/mol$. Moles of $CO_2 = \frac{	ext{given mass}}{	ext{molar mass}} = \frac{4.4 \ g}{44 \ g/mol} = 0.1 \ mol$. Number of molecules of $CO_2 = 	ext{moles} 	imes N_A = 0.1 	imes 6.022 	imes 10^{23} = 6.022 	imes 10^{22}$ molecules. Since $1$ molecule of $CO_2$ contains $2$ oxygen atoms,the number of oxygen atoms $= 2 	imes (6.022 	imes 10^{22}) = 12.044 	imes 10^{22} = 1.2044 	imes 10^{23}$ atoms. Thus,the number of oxygen atoms is approximately $1.2 	imes 10^{23}$.

The number of oxygen atoms in $4.4 \ g$ of $CO_2$ is approximately:

Similar Questions

What is the numerical value of $\frac{N}{n}$? (Where $N$ is the number of molecules in a given gas sample and $n$ is the number of moles of the gas.)

At $STP$,$32 \ g$ of $O_2$ contains $6.022 \times 10^{23}$ molecules. How many atoms does $32 \ g$ of sulfur $(S)$ contain under the same conditions?

What is the total number of electrons present in one mole of ethane?

How many grams of $H_2O$ are present in $0.25 \ mol$ of it (in $g$)?

How many moles are present in $0.224 \ L$ of an ideal $H_2$ gas at $STP$ (in $mol$)? (Assume molar volume $= 22.4 \ L \ mol^{-1}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module