The number of oxygen atoms in 4.4 g of CO_2 | vedclass

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Question

(A) Molar mass of $CO_2 = 12 + (2 	imes 16) = 44 \ g/mol$. Number of moles of $CO_2 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{4.4 \ g}{44

Vedclass · Accepted Answer

$1.2 	imes 10^{23}$

Vedclass · Answer

(A) Molar mass of $CO_2 = 12 + (2 	imes 16) = 44 \ g/mol$. Number of moles of $CO_2 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{4.4 \ g}{44 \ g/mol} = 0.1 \ mol$. $1$ molecule of $CO_2$ contains $2$ oxygen atoms. Therefore,$1$ mole of $CO_2$ contains $2 	imes 6.022 	imes 10^{23}$ oxygen atoms. Number of oxygen atoms in $0.1 \ mol$ of $CO_2 = 0.1 	imes 2 	imes 6.022 	imes 10^{23} = 1.2044 	imes 10^{23}$ oxygen atoms. Thus,the number of oxygen atoms is approximately $1.2 	imes 10^{23}$.

The number of oxygen atoms in $4.4 \ g$ of $CO_2$ is,

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