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(D) The atomic number of the element with $55$ protons is $Z = 55$,which is Cesium $(Cs)$.The electronic configuration of $Cs$ is $[Xe] \, 6s^1$.In th

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$10$

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(D) The atomic number of the element with $55$ protons is $Z = 55$,which is Cesium $(Cs)$.The electronic configuration of $Cs$ is $[Xe] \, 6s^1$.In the unipositive state $(Cs^+)$,the $6s^1$ electron is removed,resulting in the configuration $[Xe]$.The electronic configuration of Xenon $(Xe)$ is $1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6 \, 3d^{10} \, 4s^2 \, 4p^6 \, 4d^{10} \, 5s^2 \, 5p^6$.The $s$-electrons are present in $1s, 2s, 3s, 4s,$ and $5s$ orbitals.Total number of $s$-electrons = $2 + 2 + 2 + 2 + 2 = 10$.

The number of $s$-electrons present in an ion with $55$ protons in its unipositive state is

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