The number of stereoisomers possible for a co | vedclass

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(B) The molecule exhibits both geometrical and optical isomerism.The compound $CH_3-CH=CH-CH(OH)-CH_3$ contains one carbon-carbon double bond $(C=C)$

Vedclass · Accepted Answer

$4$

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(B) The molecule exhibits both geometrical and optical isomerism.The compound $CH_3-CH=CH-CH(OH)-CH_3$ contains one carbon-carbon double bond $(C=C)$ that can exhibit geometrical $(cis-trans)$ isomerism.It also contains one chiral carbon atom $(C^*)$ at the $C-4$ position,which can exhibit optical isomerism.Since the double bond and the chiral center are not symmetrically related in a way that would create meso compounds,the total number of stereoisomers is given by $2^n$,where $n$ is the number of stereogenic centers.Here,$n = 2$ (one double bond + one chiral center).Therefore,the total number of stereoisomers = $2^2 = 4$.

The number of stereoisomers possible for a compound of the molecular formula $CH_3-CH=CH-CH(OH)-CH_3$ is:

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$A$ naturally occurring substance has the constitution shown below. How many stereoisomers may have this constitution?

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