Easy
The number of unpaired electrons in nitrogen is
- A$1$
- B$3$
- C$2$
- DNone of these
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Similar Questions
Which of the following ions does not have the same electronic configuration as $Ne$?
Medium
View SolutionNitrogen has the electronic configuration $1s^2 2s^2 2p_x^1 2p_y^1 2p_z^1$ and not $1s^2 2s^2 2p_x^2 2p_y^1 2p_z^0$,which is determined by:
Easy
View SolutionConsider the following sets of quantum numbers:
$Set$ $(n)-(l)-(m)-(s)$ $(i)$ $(3)-(2)-(1)-(+1/2)$ $(ii)$ $(2)-(2)-(1)-(+1/2)$ $(iii)$ $(4)-(3)-(-2)-(-1/2)$ $(iv)$ $(1)-(0)-(-1)-(-1/2)$ $(v)$ $(3)-(2)-(3)-(+1/2)$
Which of the following sets of quantum numbers is not possible?
| $Set$ | $(n)-(l)-(m)-(s)$ |
| $(i)$ | $(3)-(2)-(1)-(+1/2)$ |
| $(ii)$ | $(2)-(2)-(1)-(+1/2)$ |
| $(iii)$ | $(4)-(3)-(-2)-(-1/2)$ |
| $(iv)$ | $(1)-(0)-(-1)-(-1/2)$ |
| $(v)$ | $(3)-(2)-(3)-(+1/2)$ |
Which of the following sets of quantum numbers is not possible?
MediumAIPMT 2007
View SolutionAssertion : An orbital designated by $n = 3, l = 1$ has double dumb-bell shape.
Reason : It belongs to $p-$subshell.
Reason : It belongs to $p-$subshell.
MediumAIIMS 2011
View SolutionThe electronic configuration of fluorine is
Easy
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