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(D) The atomic number of $Co$ is $27$. The electronic configuration of $Co$ is $[Ar] 3d^7 4s^2$.In the complex ion $[CoF_6]^{3-}$,let the oxidation st

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$4$

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(D) The atomic number of $Co$ is $27$. The electronic configuration of $Co$ is $[Ar] 3d^7 4s^2$.In the complex ion $[CoF_6]^{3-}$,let the oxidation state of $Co$ be $x$. Then $x + 6(-1) = -3$,which gives $x = +3$.The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.Since $F^-$ is a weak field ligand,it does not cause pairing of electrons in the $3d$ orbitals.According to crystal field theory,for $d^6$ configuration in an octahedral field with weak ligands,the distribution is $t_{2g}^4 e_g^2$.The number of unpaired electrons is $4$.

The number of unpaired electrons in the complex ion $[CoF_6]^{3-}$ is (Atomic number of $Co = 27$).

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