The number of water molecules is maximum in

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(C) To find the number of water molecules,we calculate the number of moles in each option:$A$. $1.8 \ g$ of $H_2O = \frac{1.8 \ g}{18 \ g/mol} = 0.1 \

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$18 \ moles$ of water

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(C) To find the number of water molecules,we calculate the number of moles in each option:$A$. $1.8 \ g$ of $H_2O = \frac{1.8 \ g}{18 \ g/mol} = 0.1 \ mol$$B$. $18 \ g$ of $H_2O = \frac{18 \ g}{18 \ g/mol} = 1 \ mol$$C$. $18 \ moles$ of $H_2O = 18 \ mol$$D$. $18$ molecules of $H_2O = \frac{18}{6.022 	imes 10^{23}} \ mol$Since the number of molecules is directly proportional to the number of moles $(N = n 	imes N_A)$,the option with the highest number of moles will have the maximum number of molecules.Therefore,$18 \ moles$ of water contains the maximum number of molecules.

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