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(B) The magnetic quantum number $m_l$ ranges from $-l$ to $+l$. For a given subshell,the maximum value of $m_l$ is equal to $l$. Given $m_l = 3$,we ha

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$4$

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(B) The magnetic quantum number $m_l$ ranges from $-l$ to $+l$. For a given subshell,the maximum value of $m_l$ is equal to $l$. Given $m_l = 3$,we have $l = 3$.The azimuthal quantum number $l$ ranges from $0$ to $n-1$. For the maximum value of $l$ in a given orbit $n$,$l = n-1$.Substituting $l = 3$,we get $3 = n - 1$,which implies $n = 4$.According to the Bohr model,the number of waves made by an electron in an orbit is equal to the principal quantum number $n$.Therefore,the number of waves $= n = 4$.Thus,the correct option is $B$.

The number of waves made by a Bohr electron in an orbit of maximum magnetic quantum number $3$ is

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