The number of ways of arranging $9$ men and $5$ women around a circular table so that no two women come together are

The number of ways in which $6$ men and $5$ women can sit at a round table,if no two women sit together,is:

$A$ family consisting of a mother,father,and their $8$ children ($4$ boys and $4$ girls) are to be seated at a round table in a party. How many ways can this be done if the mother and father sit together and the males and females alternate?

$A$ person invites $8$ guests to a dinner and places $5$ of them at one table and the remaining $3$ at another,both the tables being round. The number of ways in which the guests can be arranged is

The number of ways in which $5$ boys and $4$ girls can sit around a circular table such that no two girls sit together is:

In how many ways can $5$ men and $2$ women be seated around a circular table such that the two women do not sit together?