The number of ways of distributing $3$ dozen fruits (no two fruits are identical) to $9$ persons such that each gets the same number of fruits is
- A$\frac{36!}{(9!)^4}$
- B$\frac{36!}{(4!)^9}$
- C${ }^{36} P_9 \times 4!$
- D$\frac{36!}{4!(9!)^4}$
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