The number of ways of selecting 15 teams from | vedclass

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(B) To form $15$ teams,each consisting of one man and one woman from $15$ men and $15$ women,we proceed as follows:$1$. For the first team,we can sele

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$(15!)^2$

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(B) To form $15$ teams,each consisting of one man and one woman from $15$ men and $15$ women,we proceed as follows:$1$. For the first team,we can select $1$ man out of $15$ in $15$ ways and $1$ woman out of $15$ in $15$ ways. Total ways = $15 	imes 15$.$2$. For the second team,we select $1$ man out of the remaining $14$ and $1$ woman out of the remaining $14$. Total ways = $14 	imes 14$.$3$. Continuing this process,the total number of ways to form the teams is the product of the number of ways to form each team:Total ways = $(15 	imes 15) 	imes (14 	imes 14) 	imes \dots 	imes (1 	imes 1)$Total ways = $(15 	imes 14 	imes \dots 	imes 1) 	imes (15 	imes 14 	imes \dots 	imes 1)$Total ways = $(15!)^2$.

The number of ways of selecting $15$ teams from $15$ men and $15$ women,such that each team consists of one man and one woman,is

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