The numerical value of the charge on either p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a steady state,the capacitor acts as an open circuit,meaning no current flows through the branch containing the capacitor.The circuit effective

Vedclass · Accepted Answer

$\frac{CE R_2}{R_2 + r}$

Vedclass · Answer

(C) In a steady state,the capacitor acts as an open circuit,meaning no current flows through the branch containing the capacitor.The circuit effectively consists of the battery $E$ with internal resistance $r$ connected in series with the resistor $R_2$.The current $I$ flowing through the circuit is given by $I = \frac{E}{R_2 + r}$.The potential difference $V$ across the capacitor is equal to the potential difference across the resistor $R_2$,as they are connected in parallel.Thus,$V = I R_2 = \frac{E R_2}{R_2 + r}$.The charge $q$ on the capacitor is given by $q = CV$.Substituting the value of $V$,we get $q = C \left( \frac{E R_2}{R_2 + r} \right) = \frac{CE R_2}{R_2 + r}$.

The numerical value of the charge on either plate of the capacitor $C$ shown in the figure is

Similar Questions

If $\alpha+\beta=-2$ and $\alpha^3+\beta^3=-56$,then the quadratic equation whose roots are $\alpha$ and $\beta$ is

Which of the following molecules is electron-deficient?

The value of $k$ for which the equation $x^2-4xy-y^2+6x+2y+k=0$ represents a pair of straight lines is equal to ........

Compared to blood,our lymph has:

In order to eliminate the first degree terms from the equation $2x^2+4xy+5y^2-4x-22y+7=0$,the point to which the origin is to be shifted is

Vedclass Test Series

Exam Paper Generator

Online Exam Module