The observations 56, 58, 63, x-5, x+1, 75, 81 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given observations are $56, 58, 63, x-5, x+1, 75, 81, 85$. Total number of observations $n = 8$,which is an even number. For an even number of

Vedclass · Accepted Answer

$69$

Vedclass · Answer

(B) The given observations are $56, 58, 63, x-5, x+1, 75, 81, 85$. Total number of observations $n = 8$,which is an even number. For an even number of observations,the median is the average of the $(\frac{n}{2})^{th}$ and $(\frac{n}{2} + 1)^{th}$ terms. Here,$n = 8$,so the median is the average of the $4^{th}$ and $5^{th}$ terms. $4^{th}$ term $= x-5$ $5^{th}$ term $= x+1$ Median $= \frac{(x-5) + (x+1)}{2} = 67$ $\frac{2x - 4}{2} = 67$ $x - 2 = 67$ $x = 69$.

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Frequency	$5$	$7$	$12$	$9$	$13$	$5$

The observations $56, 58, 63, x-5, x+1, 75, 81, 85$ have been arranged in ascending order. If the median of the data is $67$,find the value of $x$.

Similar Questions

The range of the observations: $7, 9, 7, 5, 6, 6, 9, 18, 8, 8, 6$ is ..........

Draw a histogram for the data given below:

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$

Frequency $5$ $7$ $12$ $9$ $13$ $5$

The observation which is repeated most often in an ungrouped data is called .......... of the data.

Mean of $50$ observations was found to be $80.4$. But later on,it was discovered that $96$ was misread as $69$ at one place. Find the correct mean.

Find the median of the observation: $62, 67, 82, 71, 75, 77, 63, 91$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module