The octahedral diamagnetic low spin complex a | vedclass

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Question

(D) $(A) [NiCl_4]^{2-}$: $Ni^{2+} = [Ar] 3d^8$. $Cl^-$ is a weak field ligand,so it is paramagnetic,high spin,and tetrahedral.$(B) [CoCl_6]^{3-}$: $Co

Vedclass · Accepted Answer

$[Co(NH_3)_6]^{3+}$

Vedclass · Answer

(D) $(A) [NiCl_4]^{2-}$: $Ni^{2+} = [Ar] 3d^8$. $Cl^-$ is a weak field ligand,so it is paramagnetic,high spin,and tetrahedral.$(B) [CoCl_6]^{3-}$: $Co^{3+} = [Ar] 3d^6$. $Cl^-$ is a weak field ligand,so it is paramagnetic,high spin,and octahedral.$(C) [CoF_6]^{3-}$: $Co^{3+} = [Ar] 3d^6$. $F^-$ is a weak field ligand,so it is paramagnetic,high spin,and octahedral.$(D) [Co(NH_3)_6]^{3+}$: $Co^{3+} = [Ar] 3d^6$. $NH_3$ is a strong field ligand,which causes pairing of electrons in $3d$ orbitals. Thus,it is diamagnetic,low spin,and octahedral.

List-$I$ (Compound)	List-$II$ (Hybridization of Central atom)
$A. [Ni(NH_3)_6]^{2+}$	$1. sp^3$
$B. [PtCl_4]^{2-}$	$2. sp^3d^2$
$C. [Ni(CO)_4]$	$3. dsp^2$
$D. [Co(ox)_3]^{3-}$	$4. d^2sp^3$

The octahedral diamagnetic low spin complex among the following is

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