The one that is $NOT$ suitable for the removal of permanent hardness of water is :

  • A
    Treatment with sodium carbonate
  • B
    Calgon's method
  • C
    Clark's method
  • D
    Ion-exchange method

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Match the reactants in List-$I$ with the products in List-$II$.
List-$I$List-$II$
$(a). H_2O + H_2S$$(i). (H_3O^{+}, HS^{-})$
$(b). H_2O + N^{3-}$$(ii). (NH_3, OH^{-})$
$(c). H_2O + SiCl_4$$(iii). (OH^{-}, H_3S^{+})$
$(d). H_2O + F_2$$(iv). (SiO_2, HCl)$
$(v). (SiO_4^{4-}, Cl_2)$
$(vi). (O_2, F^{-})$
$(vii). (HF, OH^{-})$
$(viii). (OH^{-}, NH_3)$

Observe the following statements:
$1.$ Heavy water is harmful for the growth of animals.
$2.$ Heavy water reacts with $Al_4C_3$ and forms $\text{deuterated acetylene}$.
$3.$ $BaCl_2 \cdot 2D_2O$ is an example of $\text{interstitial deuterate}$.
The correct statements are:

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