The optically active molecule is

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(C) An optically active molecule must lack a plane of symmetry or a center of inversion. In option $(A)$, the molecule has a plane of symmetry, making

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(C) An optically active molecule must lack a plane of symmetry or a center of inversion. In option $(A)$, the molecule has a plane of symmetry, making it a meso compound. In option $(B)$, the molecule has a plane of symmetry, making it a meso compound. In option $(C)$, the molecule has different functional groups at the ends ($COOMe$ and $COOH$), which prevents the existence of a plane of symmetry, thus making it optically active. In option $(D)$, the molecule has a plane of symmetry, making it a meso compound. Therefore, only molecule $(C)$ is optically active.

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