(A) In $K_2Cr_2O_7$,the oxidation state of $Cr$ is $+6$,which corresponds to a $d^0$ configuration. Thus,no $d-d$ transition is possible.In $KMnO_4$,t

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Charge transfer transition in both.

(A) In $K_2Cr_2O_7$,the oxidation state of $Cr$ is $+6$,which corresponds to a $d^0$ configuration. Thus,no $d-d$ transition is possible.In $KMnO_4$,the oxidation state of $Mn$ is $+7$,which corresponds to a $d^0$ configuration. Thus,no $d-d$ transition is possible.The intense colours in both compounds arise due to charge transfer transitions from the oxygen ligands to the metal centre.

Class 12 Chemistry d-and f-Block Elements Compounds of Transitional elements

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The orange colour of $K_2Cr_2O_7$ and purple colour of $KMnO_4$ is due to

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A
Charge transfer transition in both.
B
$d \rightarrow d$ transition in $KMnO_4$ and charge transfer transitions in $K_2Cr_2O_7$.
C
$d \rightarrow d$ transition in $K_2Cr_2O_7$ and charge transfer transitions in $KMnO_4$.
D
$d \rightarrow d$ transition in both.