The order and degree of the differential equa | vedclass

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Question

(A) Given differential equation is $\left[1+\frac{1}{(\frac{dy}{dx})^{2}}\right]^{\frac{5}{3}}=5 \frac{d^{2}y}{dx^{2}}$.To find the order and degree,w

Vedclass · Accepted Answer

$2, 3$

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(A) Given differential equation is $\left[1+\frac{1}{(\frac{dy}{dx})^{2}}\right]^{\frac{5}{3}}=5 \frac{d^{2}y}{dx^{2}}$.To find the order and degree,we first eliminate the fractional exponent by raising both sides to the power of $3$:$\left[1+\frac{1}{(\frac{dy}{dx})^{2}}\right]^{5} = (5 \frac{d^{2}y}{dx^{2}})^{3}$$\left[\frac{(\frac{dy}{dx})^{2}+1}{(\frac{dy}{dx})^{2}}\right]^{5} = 125 (\frac{d^{2}y}{dx^{2}})^{3}$$((\frac{dy}{dx})^{2}+1)^{5} = 125 (\frac{d^{2}y}{dx^{2}})^{3} (\frac{dy}{dx})^{10}$The highest order derivative present is $\frac{d^{2}y}{dx^{2}}$,so the order is $2$.The power of the highest order derivative after making the equation a polynomial in derivatives is $3$.Thus,the order is $2$ and the degree is $3$.

The order and degree of the differential equation $\left[1+\frac{1}{(\frac{dy}{dx})^{2}}\right]^{\frac{5}{3}}=5 \frac{d^{2}y}{dx^{2}}$ are respectively:

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