The order of equivalent conductances at infin | vedclass

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(B) At infinite dilution, the equivalent conductance depends on the ionic mobility of the ions in the solution.In aqueous solution, the $Li^+$ ion has

Vedclass · Accepted Answer

$KCl > NaCl > LiCl$

Vedclass · Answer

(B) At infinite dilution, the equivalent conductance depends on the ionic mobility of the ions in the solution.In aqueous solution, the $Li^+$ ion has the smallest size and the highest charge density, causing it to be highly hydrated.Due to this high degree of hydration, the effective size of the hydrated $Li^+$ ion is the largest, which results in the lowest ionic mobility.Conversely, the $K^+$ ion has the largest size and the lowest charge density, resulting in the least hydration and the smallest effective size.Therefore, the ionic mobility follows the order $K^+ > Na^+ > Li^+$.Since equivalent conductance at infinite dilution is directly proportional to ionic mobility, the order is $KCl > NaCl > LiCl$.

The order of equivalent conductances at infinite dilution for $LiCl$, $NaCl$, and $KCl$ is:

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