The order of reactivity of phenol (I),nitrobe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Nitration is an electrophilic aromatic substitution reaction. The rate of this reaction depends on the electron density of the aromatic ring. Grou

Vedclass · Accepted Answer

$(I) > (III) > (II)$

Vedclass · Answer

(C) Nitration is an electrophilic aromatic substitution reaction. The rate of this reaction depends on the electron density of the aromatic ring. Groups that increase electron density (electron-donating groups) activate the ring,while groups that decrease electron density (electron-withdrawing groups) deactivate the ring. In phenol $(I)$,the $-OH$ group exerts a strong $+R$ (resonance) effect,which significantly increases the electron density of the ring,making it highly reactive. In benzene $(III)$,there is no substituent to alter the electron density. In nitrobenzene $(II)$,the $-NO_2$ group exerts a strong $-R$ effect,which significantly decreases the electron density of the ring,making it the least reactive. Therefore,the order of reactivity is $(I) > (III) > (II)$.

List-$I$ (Compound)	List-$II$ $(pK_a)$
$A$. $p-$Nitrophenol	$I$. $7.1$
$B$. Phenol	$II$. $10.0$
$C$. Ethanol	$III$. $15.9$
$D$. $p-$Cresol	$IV$. $10.2$

The order of reactivity of phenol $(I)$,nitrobenzene $(II)$,and benzene $(III)$ towards nitration is:

Similar Questions

The major product of the following reaction is:

The reaction which involves dichlorocarbene as an electrophile is,

Match the following:
List-$I$ (Compound) List-$II$ $(pK_a)$
$A$. $p-$Nitrophenol $I$. $7.1$
$B$. Phenol $II$. $10.0$
$C$. Ethanol $III$. $15.9$
$D$. $p-$Cresol $IV$. $10.2$
The correct answer is

Which of the following statements is not correct?

The product of the following reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module