The order of relative reactivity of the given | vedclass

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Question

(A) The $S_N2$ reaction mechanism is highly sensitive to steric hindrance. In $S_N2$ reactions,the nucleophile attacks from the backside,and as the nu

Vedclass · Accepted Answer

$PhCH_2Cl > PhCHClCH_3 > PhCCl(CH_3)_2$

Vedclass · Answer

(A) The $S_N2$ reaction mechanism is highly sensitive to steric hindrance. In $S_N2$ reactions,the nucleophile attacks from the backside,and as the number of alkyl groups attached to the carbon bearing the leaving group increases,the steric hindrance increases,making the attack more difficult. The order of reactivity for $S_N2$ is: $	ext{primary} > 	ext{secondary} > 	ext{tertiary}$. In the given compounds: $1$. $PhCH_2Cl$ is a primary halide (least hindered). $2$. $PhCHClCH_3$ is a secondary halide. $3$. $PhCCl(CH_3)_2$ is a tertiary halide (most hindered). Therefore,the order of reactivity is $PhCH_2Cl > PhCHClCH_3 > PhCCl(CH_3)_2$.

The order of relative reactivity of the given halides towards $S_N2$ reaction is :

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