The osmotic pressure of equimolar solutions of $BaCl_2$,$NaCl$,and glucose follows the order:

  • A
    $BaCl_2 > NaCl >$ Glucose
  • B
    Glucose $> NaCl > BaCl_2$
  • C
    $NaCl > BaCl_2 >$ Glucose
  • D
    $NaCl >$ Glucose $> BaCl_2$

Explore More

Similar Questions

The ideal method to determine osmotic pressure is ...... .

$A$ solution is made by dissolving $20 \ g$ of a substance in $500 \ mL$ of water. Its osmotic pressure was found to be $600 \ mm$ of $Hg$ at $15 \ ^oC$. The molecular weight of the substance is

The osmotic pressure of a living cell is $12 \ atm$ at $300 \ K$. The strength of sodium chloride solution that is isotonic with the living cell at this temperature is $...... \ g \ L^{-1}$. (Nearest integer)
Given : $R = 0.08 \ L \ atm \ K^{-1} \ mol^{-1}$
Assume complete dissociation of $NaCl$
(Given : Molar mass of $Na$ and $Cl$ are $23$ and $35.5 \ g \ mol^{-1}$ respectively.)

Calculate the osmotic pressure exerted by a solution containing $0.822 \ g$ of solute in $300 \ mL$ of water at $300 \ K$. (Molar mass of solute $= 340 \ g \ mol^{-1}, R = 0.0821 \ L \ atm \ mol^{-1} \ K^{-1}$) (in $atm$)

The osmotic pressure of $2.22\ \%\ (w/v)$ $CaCl_2$ solution at $27\ ^oC$ is $(R = 0.08\ L\ atm\ K^{-1}\ mol^{-1})$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo