The outer electronic structure of lawrencium (atomic number $103$) is
- A$Rn\, 5f^{13} \,7s^2 \,7p^2$
- B$Rn\, 5f^{13} \,6d^1 \,7s^1 \,7p^2$
- C$Rn\, 5f^{14} \,7s^1 \,7p^2$
- D$Rn\, 5f^{14} \,6d^1 \,7s^2$
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Similar Questions
The electronic configuration of Einsteinium is : (Given atomic number of Einsteinium $= 99$)
Which among the following is an actinoid element?
Provide the primary differences (comparison) between Lanthanoids and Actinoids.
Medium
View Solution$Ln$ (Lanthanide) $\xrightarrow{\text{With Halogen}} X$
$Ln$ (Lanthanide) $\xrightarrow{\text{Burn With } O_2} Y$
$Ln$ (Lanthanide) $\xrightarrow{\text{Heated with } N_2} Z$
$X, Y$ and $Z$ are respectively:-
$Ln$ (Lanthanide) $\xrightarrow{\text{Burn With } O_2} Y$
$Ln$ (Lanthanide) $\xrightarrow{\text{Heated with } N_2} Z$
$X, Y$ and $Z$ are respectively:-
Difficult
View SolutionMost common oxidation states of $Ce$ are
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