The output Y when all the three inputs A, B, | vedclass

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(A) The given circuit consists of a $NAND$ gate with inputs $A$ and $B$, a $NOT$ gate with input $C$, and an $OR$ gate that combines their outputs.The

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$1, 0$

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(A) The given circuit consists of a $NAND$ gate with inputs $A$ and $B$, a $NOT$ gate with input $C$, and an $OR$ gate that combines their outputs.The Boolean expression for the output $Y$ is $Y = (\overline{A \cdot B}) + \overline{C}$.Case $1$: When all inputs $A, B, C$ are low $(0, 0, 0)$:$A = 0, B = 0 \implies A \cdot B = 0 \implies \overline{A \cdot B} = 1$.$C = 0 \implies \overline{C} = 1$.$Y = 1 + 1 = 1$.Case $2$: When all inputs $A, B, C$ are high $(1, 1, 1)$:$A = 1, B = 1 \implies A \cdot B = 1 \implies \overline{A \cdot B} = 0$.$C = 1 \implies \overline{C} = 0$.$Y = 0 + 0 = 0$.Thus, the output sequence is $1, 0$.

The output $Y$ when all the three inputs $A, B, C$ are first low and then high will be

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The truth table given below is for ($A$ and $B$ are the inputs,$Y$ is the output).
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