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(D) The circuit consists of two $AND$ gates and one $OR$ gate. The top $AND$ gate receives inputs $A$ and $B$, producing output $Y_1 = A \cdot B$. The

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(D) The circuit consists of two $AND$ gates and one $OR$ gate. The top $AND$ gate receives inputs $A$ and $B$, producing output $Y_1 = A \cdot B$. The bottom $AND$ gate receives inputs $A$ and $\bar{B}$ (due to the $NOT$ gate/inversion bubble), producing output $Y_2 = A \cdot \bar{B}$. The final $OR$ gate combines these to give $Y = Y_1 + Y_2 = A \cdot B + A \cdot \bar{B}$.Using Boolean algebra: $Y = A(B + \bar{B}) = A(1) = A$.Therefore, the output waveform $Y$ must be identical to the input waveform $A$.Comparing this with the given options, the waveform for $A$ is $0$ from $t=0$ to $1$, $1$ from $t=1$ to $2$, and $1$ from $t=2$ to $3$. Option $D$ matches this behavior.

The output $Y$ for the given inputs $A$ and $B$ to the circuit is:

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