The output D for the given circuit is: | vedclass

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(A) $1$. The circuit consists of an $OR$ gate,a $NOT$ gate,and an $AND$ gate.$2$. The inputs to the $OR$ gate are $A$ and $B$,so its output is $Y' = A

Vedclass · Accepted Answer

$(A + B) \cdot \overline{B}$

Vedclass · Answer

(A) $1$. The circuit consists of an $OR$ gate,a $NOT$ gate,and an $AND$ gate.$2$. The inputs to the $OR$ gate are $A$ and $B$,so its output is $Y' = A + B$.$3$. The input $B$ is also passed through a $NOT$ gate,so its output is $\overline{B}$.$4$. The $AND$ gate takes $Y'$ and $\overline{B}$ as inputs.$5$. Therefore,the final output $D$ is $D = Y' \cdot \overline{B} = (A + B) \cdot \overline{B}$.

The output $D$ for the given circuit is:

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