The oxidation number of Pt in [Pt(C_2H_4)Cl_3 | vedclass

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(B) Let $x$ be the oxidation state of $Pt$ in $[Pt(C_2H_4)Cl_3]^{-}$.Since the overall charge on the complex is $-1$,the sum of oxidation states of al

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$+2$

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(B) Let $x$ be the oxidation state of $Pt$ in $[Pt(C_2H_4)Cl_3]^{-}$.Since the overall charge on the complex is $-1$,the sum of oxidation states of all elements in it should be equal to $-1$.Ethylene $(C_2H_4)$ is a neutral ligand with an oxidation state of $0$.Chlorine $(Cl)$ as a ligand has an oxidation state of $-1$.Therefore,$x + 0 + 3(-1) = -1$.$x - 3 = -1$.$x = +2$.

The oxidation number of $Pt$ in $[Pt(C_2H_4)Cl_3]^{-}$ is

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