The oxidation number of iron in potassium fer | vedclass

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(A) The chemical formula for potassium ferrocyanide is $K_4[Fe(CN)_6]$.Let the oxidation number of iron $(Fe)$ be $x$.The oxidation number of potassiu

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(A) The chemical formula for potassium ferrocyanide is $K_4[Fe(CN)_6]$.Let the oxidation number of iron $(Fe)$ be $x$.The oxidation number of potassium $(K)$ is $+1$ and the cyanide ligand $(CN)$ is $-1$.Applying the rule that the sum of oxidation states in a neutral complex is zero:$4(+1) + x + 6(-1) = 0$$4 + x - 6 = 0$$x - 2 = 0$$x = +2$.Therefore,the oxidation number of iron is $2$.

The oxidation number of iron in potassium ferrocyanide is

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