The oxidation number of sulphur in S_8,S_2F_2 | vedclass

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Question

(A) $1$. For $S_8$: Since it is a homoatomic molecule,the oxidation number of $S$ is $0$.$2$. For $S_2F_2$: Let the oxidation number of $S$ be $x$. Si

Vedclass · Accepted Answer

$0, +1, -2$

Vedclass · Answer

(A) $1$. For $S_8$: Since it is a homoatomic molecule,the oxidation number of $S$ is $0$.$2$. For $S_2F_2$: Let the oxidation number of $S$ be $x$. Since the oxidation number of $F$ is $-1$,we have $2x + 2(-1) = 0$,which gives $2x = 2$,so $x = +1$.$3$. For $H_2S$: Let the oxidation number of $S$ be $x$. Since the oxidation number of $H$ is $+1$,we have $2(+1) + x = 0$,which gives $x = -2$.Thus,the oxidation numbers are $0, +1, -2$.

The oxidation number of sulphur in $S_8$,$S_2F_2$ and $H_2S$ respectively are:

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