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(C) For $[Pt(NH_3)_2Cl(NO_2)]$: Let the oxidation number of $Pt = x$. $NH_3$ is a neutral ligand $(0)$,$Cl^-$ is $-1$,and $NO_2^-$ is $-1$. $x + 2(0)

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$+2; +3$

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(C) For $[Pt(NH_3)_2Cl(NO_2)]$: Let the oxidation number of $Pt = x$. $NH_3$ is a neutral ligand $(0)$,$Cl^-$ is $-1$,and $NO_2^-$ is $-1$. $x + 2(0) + (-1) + (-1) = 0$ $x - 2 = 0 \implies x = +2$. For $[CoCl_2(en)_2]^{\oplus}$: Let the oxidation number of $Co = y$. $en$ (ethylenediamine) is a neutral ligand $(0)$ and $Cl^-$ is $-1$. $y + 2(-1) + 2(0) = +1$ $y - 2 = +1 \implies y = +3$. Thus,the oxidation states are $+2$ and $+3$ respectively.

The oxidation number of the central metal in $[Pt(NH_3)_2Cl(NO_2)]$ and $[CoCl_2(en)_2]^{\oplus}$,respectively,are

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