The oxidation state of $N$ in $HNO_4$ is
- A$+7$
- B$+5$
- C$-3$
- D$+3$
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Oxidation number of oxygen in potassium superoxide $(KO_2)$ is
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Compound Oxidation number $1$. $C_2H_6$ $a$. $+3$ $2$. $H_2O_2$ $b$. $+6$ $3$. $LiAlH_4$ $c$. $-3$ $4$. $HO_2^-$ $d$. $-1$ $5$. $PbSO_4$ $e$. $+1$
| Compound | Oxidation number |
|---|---|
| $1$. $C_2H_6$ | $a$. $+3$ |
| $2$. $H_2O_2$ | $b$. $+6$ |
| $3$. $LiAlH_4$ | $c$. $-3$ |
| $4$. $HO_2^-$ | $d$. $-1$ |
| $5$. $PbSO_4$ | $e$. $+1$ |
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