The oxidation state of cobalt in the followin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given molecule is $Co_2(CO)_8$.In this complex,the ligand $CO$ (carbonyl) is a neutral ligand,meaning its charge is $0$.Since the overall char

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) The given molecule is $Co_2(CO)_8$.In this complex,the ligand $CO$ (carbonyl) is a neutral ligand,meaning its charge is $0$.Since the overall charge of the molecule $Co_2(CO)_8$ is $0$,we can calculate the oxidation state of $Co$ as follows:Let the oxidation state of $Co$ be $x$.$2x + 8(0) = 0$$2x = 0$$x = 0$Therefore,the oxidation state of cobalt in the molecule is $0$.

The oxidation state of cobalt in the following molecule is

Similar Questions

Which of the following is not a $\pi -$ bonded organometallic complex?

Which of the following is called Wilkinson's catalyst?

The correct sequence of $CO$ bond order in the given compounds is:
$(P) \ Fe(CO)_5, (Q) \ CO, (R) \ H_3B \leftarrow CO, (S) \ [Mn(CO)_5]^-$

Tetraethyl lead is used as

Which of the following species show synergic bonding?

Vedclass Test Series

Exam Paper Generator

Online Exam Module