The peak voltage of the $ac$ source is equal to:

  • A
    the $rms$ value of the $ac$ source
  • B
    $\sqrt{2}$ times the $rms$ value of the $ac$ source
  • C
    $\frac{1}{\sqrt{2}}$ times the $rms$ value of the $ac$ source
  • D
    the value of voltage supplied to the circuit

Explore More

Similar Questions

The peak value of $220 \, V$ of $ac$ mains is ...... $V$.

An alternating voltage is represented by $V = 80 \sin(100 \pi t) \cos(100 \pi t) \text{ V}$. The peak voltage is (in $\text{ V}$)

The average value of alternating current over a complete cycle is

The peak value of an alternating emf $e$ given by $e = e_0 \cos \omega t$ is $10 \ V$ and its frequency is $50 \ Hz$. At time $t = \frac{1}{600} \ s$,the instantaneous e.m.f is:

The electric current in the circuit is given as $i = i_{0}(t / T)$. The r.m.s current for the period $t = 0$ to $t = T$ is . . . . . .

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo