The percentage of unoccupied volume in a simp | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Key Idea: Percentage of unoccupied volume $= 100 - 	ext{Packing efficiency}.$Packing efficiency $= \frac{	ext{Volume of one atom}}{	ext{Volume

Vedclass · Accepted Answer

$47.60$

Vedclass · Answer

(C) Key Idea: Percentage of unoccupied volume $= 100 - 	ext{Packing efficiency}.$Packing efficiency $= \frac{	ext{Volume of one atom}}{	ext{Volume of cubic unit cell}} 	imes 100\%.$For a simple cubic cell,the number of atoms per unit cell is $1$ and the relation between edge length $a$ and radius $r$ is $a = 2r.$Packing efficiency $= \frac{\frac{4}{3} \pi r^3}{(2r)^3} 	imes 100 = \frac{\frac{4}{3} \pi r^3}{8 r^3} 	imes 100 = \frac{\pi}{6} 	imes 100 \approx 52.4\%.$$	herefore$ Percentage of unoccupied volume in $SCC = 100 - 52.4 = 47.6\%.$

The percentage of unoccupied volume in a simple cubic cell is (in $\%$)

Similar Questions

In an ionic solid, anions $(B)$ are arranged in an $hcp$ array and cations $(A)$ occupy $1/2$ of the tetrahedral voids. What is the formula of the ionic compound?

What is the percentage of void space in $hcp$ and $ccp$ structures (in $\%$)?

What is the percentage of unoccupied space in $fcc$ unit cell (in $\%$)?

Percentage of free space in a body-centred cubic unit cell is ................ $\%$

Which of the following represents the hexagonal close-packed $(HCP)$ arrangement of spheres?

Vedclass Test Series

Exam Paper Generator

Online Exam Module