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(B) Given,the perimeter of the semicircular table-top is $3.60 \, m$.Converting meters to centimeters: $3.60 \, m = 360 \, cm$.The perimeter of a semi

Vedclass · Accepted Answer

$70$

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(B) Given,the perimeter of the semicircular table-top is $3.60 \, m$.Converting meters to centimeters: $3.60 \, m = 360 \, cm$.The perimeter of a semicircle is given by the formula: $P = \pi r + 2r = r(\pi + 2)$.Substituting the given values:$360 = r \left( \frac{22}{7} + 2 ight)$$360 = r \left( \frac{22 + 14}{7} ight)$$360 = r \left( \frac{36}{7} ight)$Solving for $r$:$r = 360 	imes \frac{7}{36}$$r = 10 	imes 7$$r = 70 \, cm$.Thus,the radius of the semicircular table-top is $70 \, cm$.

The perimeter of a semicircular table-top is $3.60 \, m$. Then,its radius is $\ldots \ldots \ldots \, cm$.

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