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(C) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{l}{g_{eff}}}$.For a stationary lift,the effective acceleration is $g_{eff}

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$\frac{\sqrt{3}}{2}T$

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(C) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{l}{g_{eff}}}$.For a stationary lift,the effective acceleration is $g_{eff} = g$,so $T = 2\pi \sqrt{\frac{l}{g}}$.When the lift accelerates upwards with acceleration $a = g/3$,the effective acceleration becomes $g_{eff} = g + a = g + g/3 = 4g/3$.The new time period $T'$ is given by $T' = 2\pi \sqrt{\frac{l}{4g/3}} = 2\pi \sqrt{\frac{3l}{4g}}$.We can rewrite this as $T' = \frac{\sqrt{3}}{2} \left( 2\pi \sqrt{\frac{l}{g}} \right)$.Substituting $T$ for the initial period,we get $T' = \frac{\sqrt{3}}{2}T$.

The period of a simple pendulum measured inside a stationary lift is found to be $T$. If the lift starts accelerating upwards with an acceleration of $g/3$,then the time period of the pendulum is

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