(C) The phase of a particle in $SHM$ is defined by the argument of the sine or cosine function in the displacement equation,$x(t) = A \sin(\omega t +

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Both the position and direction of motion of the particle at time $t$

(C) The phase of a particle in $SHM$ is defined by the argument of the sine or cosine function in the displacement equation,$x(t) = A \sin(\omega t + \phi)$.This phase angle $(\omega t + \phi)$ uniquely determines the state of the particle.Specifically,it provides information about both the displacement (position) of the particle relative to the equilibrium position and the direction of its velocity at that specific instant $t$.

Class 11 Physics Oscillations Position of a Particle in SHM, Displacement and Phase

Easy

The phase (at a time $t$) of a particle in simple harmonic motion tells:

A
Only the position of the particle at time $t$
B
Only the direction of motion of the particle at time $t$
C
Both the position and direction of motion of the particle at time $t$
D
Neither the position of the particle nor its direction of motion at time $t$

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Oscillations

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Position of a Particle in SHM, Displacement and Phase

$A$ particle initially at the mean position is executing simple harmonic motion with an angular frequency $\omega = \frac{\pi}{4} \text{ rad s}^{-1}$. The ratio of the distances travelled by the particle in the first second and the second second is:

DifficultAP EAMCET 2023

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$A$ particle is executing $SHM$ of amplitude $A$ about the mean position $x = 0.$ Which of the following cannot be a possible phase difference between the positions of the particle at $x = +A/2$ and $x = -A/\sqrt{2}$ (in $^o$)?

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$A$ particle executing $SHM$ of amplitude $4 \, cm$ and $T = 4 \, s$. The time taken by it to move from $+2 \, cm$ to $+2\sqrt{3} \, cm$ is

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$A$ particle executes simple harmonic motion between $x=-A$ and $x=+A$. If it takes a time $T_1$ to go from $x=0$ to $x=A/2$ and $T_2$ to go from $x=A/2$ to $x=A$,then:

MediumAP EAMCET 2020

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$A$ particle executes simple harmonic motion represented by the displacement function $x(t) = A \sin (\omega t + \phi)$. If the position and velocity of the particle at $t = 0 \, s$ are $2 \, cm$ and $2 \omega \, cm \, s^{-1}$ respectively,then its amplitude is $x \sqrt{2} \, cm$,where the value of $x$ is ..... .

MediumJEE MAIN 2021

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The phase (at a time $t$) of a particle in simple harmonic motion tells:

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$A$ particle initially at the mean position is executing simple harmonic motion with an angular frequency $\omega = \frac{\pi}{4} \text{ rad s}^{-1}$. The ratio of the distances travelled by the particle in the first second and the second second is:

$A$ particle is executing $SHM$ of amplitude $A$ about the mean position $x = 0.$ Which of the following cannot be a possible phase difference between the positions of the particle at $x = +A/2$ and $x = -A/\sqrt{2}$ (in $^o$)?

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