The points (0, 8/3),(1, 3) and (82, 30) are t | vedclass

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(D) Let the points be $A(0, 8/3)$,$B(1, 3)$,and $C(82, 30)$.To check if these points form a triangle,we calculate the area of the triangle using the f

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None of these

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(D) Let the points be $A(0, 8/3)$,$B(1, 3)$,and $C(82, 30)$.To check if these points form a triangle,we calculate the area of the triangle using the formula:$	ext{Area} = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$Substituting the values:$	ext{Area} = \frac{1}{2} |0(3 - 30) + 1(30 - 8/3) + 82(8/3 - 3)|$$	ext{Area} = \frac{1}{2} |0 + (90 - 8)/3 + 82(-1/3)|$$	ext{Area} = \frac{1}{2} |82/3 - 82/3| = 0$Since the area is $0$,the points are collinear and do not form a triangle. Therefore,the correct option is $D$.

The points $(0, 8/3)$,$(1, 3)$ and $(82, 30)$ are the vertices of

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