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(C) Let the population $3$ years ago be $P$.Given that the population increases at a rate of $5 \%$ per annum.The formula for population after $n$ yea

Vedclass · Accepted Answer

$3,20,000$

Vedclass · Answer

(C) Let the population $3$ years ago be $P$.Given that the population increases at a rate of $5 \%$ per annum.The formula for population after $n$ years is $A = P(1 + \frac{r}{100})^n$.Here,$A = 3,70,440$,$r = 5$,and $n = 3$.$3,70,440 = P(1 + \frac{5}{100})^3$$3,70,440 = P(1 + \frac{1}{20})^3$$3,70,440 = P(\frac{21}{20})^3$$3,70,440 = P 	imes \frac{9261}{8000}$$P = \frac{3,70,440 	imes 8000}{9261}$$P = 40 	imes 8000 = 3,20,000$.Thus,the population $3$ years ago was $3,20,000$.

The population of a city increases at the rate of $5 \%$ per annum. If the present population of the city is $3,70,440$,its population $3$ years ago was:

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