The position of both an electron and a helium | vedclass

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(D) According to Heisenberg's uncertainty principle,the product of uncertainty in position $(\Delta x)$ and uncertainty in momentum $(\Delta p)$ is gi

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$50 	imes 10^{-26} \, kg \, m \, s^{-1}$

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(D) According to Heisenberg's uncertainty principle,the product of uncertainty in position $(\Delta x)$ and uncertainty in momentum $(\Delta p)$ is given by: $\Delta x \cdot \Delta p \geq \frac{h}{4\pi}$.Since the uncertainty in position $(\Delta x)$ is the same for both the electron and the helium atom $(1.0 \, nm)$,the uncertainty in momentum $(\Delta p)$ must also be the same for both particles to satisfy the inequality.Given that the uncertainty in the momentum of the electron is $50 	imes 10^{-26} \, kg \, m \, s^{-1}$,the minimum uncertainty in the measurement of the momentum of the helium atom will also be $50 	imes 10^{-26} \, kg \, m \, s^{-1}$.

The position of both an electron and a helium atom is known within $1.0 \, nm$ and the momentum of the electron is known within $50 \times 10^{-26} \, kg \, m \, s^{-1}$. The minimum uncertainty in the measurement of the momentum of the helium atom is

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