(B) Let the equation of the line be $L(x, y) = 3x - 4y - 8 = 0$. For the point $(3, 4)$,we calculate $L(3, 4) = 3(3) - 4(4) - 8 = 9 - 16 - 8 = -15$. S

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(B) Let the equation of the line be $L(x, y) = 3x - 4y - 8 = 0$. For the point $(3, 4)$,we calculate $L(3, 4) = 3(3) - 4(4) - 8 = 9 - 16 - 8 = -15$. Since $L(3, 4) For the point $(2, -6)$,we calculate $L(2, -6) = 3(2) - 4(-6) - 8 = 6 + 24 - 8 = 22$. Since $L(2, -6) > 0$,the point $(2, -6)$ lies on the other side of the line. Because the values of $L(x, y)$ at these two points have opposite signs,the points lie on different sides of the line.

Class 11 Mathematics Straight Line Distance between two lines, Perpendicular distance of the line from a point, Position of point w.r.t. line

Easy

The positions of the points $(3, 4)$ and $(2, -6)$ with respect to the line $3x - 4y = 8$ are:

A
On the same side of the line
B
On different sides of the line
C
One point on the line and the other outside the line
D
Both points on the line

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Straight Line

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Distance between two lines, Perpendicular distance of the line from a point, Position of point w.r.t. line

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MediumWBJEE 2017

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Medium

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DifficultAP EAMCET 2013

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The positions of the points $(3, 4)$ and $(2, -6)$ with respect to the line $3x - 4y = 8$ are:

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