The potential difference between $A$ and $B$ in the figure is ................... $V$.

In the figure shown,battery $1$ has $emf = 6\, V$ and internal resistance $= 1\, \Omega$. Battery $2$ has $emf = 2\, V$ and internal resistance $= 3\, \Omega$. The wires have negligible resistance. What is the potential difference across the terminals of battery $2$ (in $, V$)?

As shown in the figure,a network of resistors is connected to a battery of $24\,V$ with an internal resistance of $3\,\Omega$. The currents through the resistors $R_4$ and $R_5$ are $I_4$ and $I_5$ respectively. The values of $I_4$ and $I_5$ are:

Three resistances $A, B$ and $C$ having values $3R, 6R$ and $R$ respectively form a network as shown. When a potential difference is applied across the network,the thermal powers dissipated by $A, B$ and $C$ are in the ratio:

In the circuit shown,the readings of the ammeter and voltmeter are $4\,\, A$ and $20\,\, V$ respectively. The meters are non-ideal. Then $R$ is

Two bulbs,as in the previous context ($40\, W$ and $100\, W$ bulbs rated at the same voltage),are connected in series to a $200\, V$ line. Then: