The potential difference between A and B in t | vedclass

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(D) To find the potential difference $V_A - V_B$, we apply Kirchhoff's Voltage Law $(KVL)$ along the path from $A$ to $B$.Starting from point $A$ with

Vedclass · Accepted Answer

$48$

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(D) To find the potential difference $V_A - V_B$, we apply Kirchhoff's Voltage Law $(KVL)$ along the path from $A$ to $B$.Starting from point $A$ with potential $V_A$:$1$. Moving through the $6\, \Omega$ resistor in the direction of current $(2\, A)$, the potential drops by $I 	imes R = 2 	imes 6 = 12\, V$.$2$. Moving through the $12\, V$ battery from positive to negative terminal, the potential drops by $12\, V$.$3$. Moving through the $9\, \Omega$ resistor, the potential drop is $I 	imes R = 2 	imes 9 = 18\, V$.$4$. Moving through the $4\, V$ battery from negative to positive terminal, the potential increases by $4\, V$.$5$. Moving through the $5\, \Omega$ resistor, the potential drop is $I 	imes R = 2 	imes 5 = 10\, V$.Equating this to $V_B$:$V_A - 12 - 12 - 18 + 4 - 10 = V_B$$V_A - V_B = 12 + 12 + 18 - 4 + 10$$V_A - V_B = 48\, V$.

The potential difference between $A$ and $B$ in the figure is .............. $V$.

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